What is the solution for (dy)/(dx)-2y=e^{5x} ?

The solution for (dy)/(dx)-2y=e^{5x} is y=(e^{5x})/3+c_{1}e^{2x}

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(dy)/(dx)-2y=e^{5x}

\frac{d y}{d x} - 2 y = e^{5 x}

y = \frac{e ^{5 x}}{3} + c_{1} e^{2 x}

Solution steps

\frac{d y}{d x} - 2 y = e^{5 x}

Solve linear ODE:

y = \frac{e ^{5 x}}{3} + c_{1} e^{2 x}

y = \frac{e ^{5 x}}{3} + c_{1} e^{2 x}

\frac{d}{d x} (- 5 sin (2 x))

\frac{d}{d x} (cos (x + 1))

x^{2} y^{^{''}} - 4 x y^{^{'}} - 36 y = 0

\frac{\partial}{\partial x} (x y cos (3 x) + e^{x y})

(x + 1) y^{^{'}} - y = x

What is the solution for (dy)/(dx)-2y=e^{5x} ?
The solution for (dy)/(dx)-2y=e^{5x} is y=(e^{5x})/3+c_{1}e^{2x}