What is the d/(dt)(tsin(t)+cos(t)) ?

The d/(dt)(tsin(t)+cos(t)) is tcos(t)

What is the first d/(dt)(tsin(t)+cos(t)) ?

The first d/(dt)(tsin(t)+cos(t)) is tcos(t)

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\frac{d}{d t} (t sin (t) + cos (t))

t cos (t)

Solution steps

\frac{d}{d t} (t sin (t) + cos (t))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (t sin (t)) + \frac{d}{d t} (cos (t))

\frac{d}{d t} (t sin (t)) = sin (t) + t cos (t)

\frac{d}{d t} (cos (t)) = - sin (t)

= sin (t) + t cos (t) - sin (t)

Simplify

= t cos (t)

\int \frac{( 1 - x )}{x ^{2}} d x

(1 + x)^{4}

\int \frac{1}{sin ( x )} d x

\frac{1 - 2 t}{1 + 3 t}

f (x) = x^{2} + 10 x + 242 x + 8

What is the d/(dt)(tsin(t)+cos(t)) ?
The d/(dt)(tsin(t)+cos(t)) is tcos(t)
What is the first d/(dt)(tsin(t)+cos(t)) ?
The first d/(dt)(tsin(t)+cos(t)) is tcos(t)