What is the derivative of (y^4)/8 ?

The derivative of (y^4)/8 is (y^3)/2

What is the first derivative of (y^4)/8 ?

The first derivative of (y^4)/8 is (y^3)/2

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derivative of

\frac{y ^{4}}{8}

\frac{y ^{3}}{2}

Solution steps

\frac{d}{d y} (\frac{y ^{4}}{8})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{8} \frac{d}{d y} (y^{4})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{1}{8} \cdot 4 y^{4 - 1}

Simplify

\frac{1}{8} \cdot 4 y^{4 - 1} : \frac{y ^{3}}{2}

= \frac{y ^{3}}{2}

\int \frac{1}{( x + 1 ) x ^{2} + 2 x} d x

x \to 0 + lim (x^{5 s i n (x)})

\frac{\partial}{\partial z} (4 x ln (y) + y ln (z) - x)

(x - 4 y - 3) d x - (x - 6 y - 5) d y = 0

n \to \infty lim (cos (n))

What is the derivative of (y^4)/8 ?
The derivative of (y^4)/8 is (y^3)/2
What is the first derivative of (y^4)/8 ?
The first derivative of (y^4)/8 is (y^3)/2