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Popular >

y^'=6x+y,y(0)=8

Solution

y^{^{'}} = 6 x + y, y (0) = 8

Solution

y = - 6 (x + 1) + 14 e^{x}

Solution steps

y^{'} (x) = 6 x + y

Solve linear ODE:

y = - 6 (x + 1) + 14 e^{x}

y = - 6 (x + 1) + 14 e^{x}

Popular Examples

integral from 0 to ln(2) of e^{-x}

\int_{0}^{l n (2)} e^{- x} d x

(dy)/(dx)=(sec(y))/((x-1)^2)

\frac{d y}{d x} = \frac{sec ( y )}{( x - 1 ) ^{2}}

integral of (-x^2-2x)

\int (- x^{2} - 2 x) d x

area y=sqrt(x),y= 1/2 x,x=9 area

y = x, y = \frac{1}{2} x, x = 9

derivative of 1/(x^2+2x+1)

\frac{d}{d x} (\frac{1}{x ^{2} + 2 x + 1})

Frequently Asked Questions (FAQ)

What is the solution for y^'=6x+y,y(0)=8 ?
The solution for y^'=6x+y,y(0)=8 is y=-6(x+1)+14e^x