What is area y=sqrt(x),y= 1/2 x,x=9 ?

The answer to area y=sqrt(x),y= 1/2 x,x=9 is 59/12

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area y=sqrt(x),y= 1/2 x,x=9

area

y = x, y = \frac{1}{2} x, x = 9

\frac{59}{12}

Decimal Notation

4.91666 \dots

Solution steps

Apply the area formula:

\int_{0}^{9} x - \frac{1}{2} x d x

Solve

\int_{0}^{9} x - \frac{1}{2} x d x : \frac{59}{12}

The area is:

= \frac{59}{12}

\frac{d}{d x} (\frac{1}{x ^{2} + 2 x + 1})

y = (s - 4) (s^{2} - 3), (1, 6)

t sin (t)

\frac{d}{d x} (\frac{x ^{4}}{4})

\int_{0}^{\frac{π}{20}} cos (5 x) d x

What is area y=sqrt(x),y= 1/2 x,x=9 ?
The answer to area y=sqrt(x),y= 1/2 x,x=9 is 59/12