What is the derivative of (x+1(x^2-1)) ?

The derivative of (x+1(x^2-1)) is 3x^2+2x-1

What is the first derivative of (x+1(x^2-1)) ?

The first derivative of (x+1(x^2-1)) is 3x^2+2x-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} ((x + 1) (x^{2} - 1))

3 x^{2} + 2 x - 1

Solution steps

\frac{d}{d x} ((x + 1) (x^{2} - 1))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x + 1, g = x^{2} - 1

= \frac{d}{d x} (x + 1) (x^{2} - 1) + \frac{d}{d x} (x^{2} - 1) (x + 1)

\frac{d}{d x} (x + 1) = 1

\frac{d}{d x} (x^{2} - 1) = 2 x

= 1 \cdot (x^{2} - 1) + 2 x (x + 1)

Simplify

1 \cdot (x^{2} - 1) + 2 x (x + 1) : 3 x^{2} + 2 x - 1

= 3 x^{2} + 2 x - 1

\frac{d}{d x} (\frac{2 tan ( x )}{x})

n = 0 \sum \infty \frac{1}{5 n + 1}

2 x^{3} - 4 x + 6

\frac{\partial}{\partial x} (5 - 3 x + 6 y - 2 x^{2} y)

(1, 6), (7, 3)

What is the derivative of (x+1(x^2-1)) ?
The derivative of (x+1(x^2-1)) is 3x^2+2x-1
What is the first derivative of (x+1(x^2-1)) ?
The first derivative of (x+1(x^2-1)) is 3x^2+2x-1