What is (\partial)/(\partial x)(5-3x+6y-2x^2y) ?

The answer to (\partial)/(\partial x)(5-3x+6y-2x^2y) is -4xy-3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)(5-3x+6y-2x^2y)

\frac{\partial}{\partial x} (5 - 3 x + 6 y - 2 x^{2} y)

- 4 x y - 3

Solution steps

\frac{\partial}{\partial x} (5 - 3 x + 6 y - 2 x^{2} y)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (5) - \frac{\partial}{\partial x} (3 x) + \frac{\partial}{\partial x} (6 y) - \frac{\partial}{\partial x} (2 x^{2} y)

\frac{\partial}{\partial x} (5) = 0

\frac{\partial}{\partial x} (3 x) = 3

\frac{\partial}{\partial x} (6 y) = 0

\frac{\partial}{\partial x} (2 x^{2} y) = 4 y x

= 0 - 3 + 0 - 4 y x

Simplify

= - 4 x y - 3

(1, 6), (7, 3)

\int x^{3} y d y

\frac{d y}{d x} = 3 y x^{2} - 3 x^{2}

\frac{d ^{2}}{d x ^{2}} (\frac{1}{x ^{9}})

\frac{d}{d x} (6 cos (5 x))

What is (\partial)/(\partial x)(5-3x+6y-2x^2y) ?
The answer to (\partial)/(\partial x)(5-3x+6y-2x^2y) is -4xy-3