What is the derivative of 3x^2+(4x/3-2) ?

The derivative of 3x^2+(4x/3-2) is 6x+4/3

What is the first derivative of 3x^2+(4x/3-2) ?

The first derivative of 3x^2+(4x/3-2) is 6x+4/3

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\frac{d}{d x} (3 x^{2} + \frac{4 x}{3} - 2)

6 x + \frac{4}{3}

Solution steps

\frac{d}{d x} (3 x^{2} + \frac{4 x}{3} - 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2}) + \frac{d}{d x} (\frac{4 x}{3}) - \frac{d}{d x} (2)

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (\frac{4 x}{3}) = \frac{4}{3}

\frac{d}{d x} (2) = 0

= 6 x + \frac{4}{3} - 0

Simplify

= 6 x + \frac{4}{3}

\frac{( y ^{^{'}} - e ^{- t} + 5 )}{y} = - 5

f (x) = 9 - x

\int 12 x^{5} y^{4} + 15 x^{4} y^{5}

ln (e + x^{2})

\int cos^{2} (x) x d x

What is the derivative of 3x^2+(4x/3-2) ?
The derivative of 3x^2+(4x/3-2) is 6x+4/3
What is the first derivative of 3x^2+(4x/3-2) ?
The first derivative of 3x^2+(4x/3-2) is 6x+4/3