What is the integral from 0 to 7 of 5/3 x ?

The integral from 0 to 7 of 5/3 x is 245/6

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integral from 0 to 7 of 5/3 x

\int_{0}^{7} \frac{5}{3} x d x

\frac{245}{6}

Decimal Notation

40.83333 \dots

Solution steps

\int_{0}^{7} \frac{5}{3} x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{5}{3} \cdot \int_{0}^{7} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{0}^{7}

= \frac{5}{3} [\frac{x ^{2}}{2}]_{0}^{7}

Compute the boundaries:

\frac{49}{2}

= \frac{5}{3} \cdot \frac{49}{2}

Simplify

= \frac{245}{6}

- \frac{1}{s ^{2} + ( 5 ) ^{2}}

\int_{- 3}^{0} 9 - x^{2} d x

\frac{3 s - 1}{( s ^{2} + 2 s + 5 )}

\frac{d y}{d x} = 3 (y^{2} + 1), y (\frac{π}{4}) = 1

y^{^{'}} - y = 2 t e^{2 t}

What is the integral from 0 to 7 of 5/3 x ?
The integral from 0 to 7 of 5/3 x is 245/6