What is the derivative of (1+x^2^5) ?

The derivative of (1+x^2^5) is 10x(1+x^2)^4

What is the first derivative of (1+x^2^5) ?

The first derivative of (1+x^2^5) is 10x(1+x^2)^4

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\frac{d}{d x} ((1 + x^{2})^{5})

10 x (1 + x^{2})^{4}

Solution steps

\frac{d}{d x} ((1 + x^{2})^{5})

Apply the chain rule:

5 (1 + x^{2})^{4} \frac{d}{d x} (1 + x^{2})

= 5 (1 + x^{2})^{4} \frac{d}{d x} (1 + x^{2})

\frac{d}{d x} (1 + x^{2}) = 2 x

= 5 (1 + x^{2})^{4} \cdot 2 x

Simplify

= 10 x (1 + x^{2})^{4}

\frac{d}{d x} (sin (2 x) \cdot 2)

\frac{d}{d x} (a e^{v} + \frac{b}{v} + \frac{c}{v ^{2}})

\frac{\partial}{\partial u} (u^{9} + v^{7})

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What is the derivative of (1+x^2^5) ?
The derivative of (1+x^2^5) is 10x(1+x^2)^4
What is the first derivative of (1+x^2^5) ?
The first derivative of (1+x^2^5) is 10x(1+x^2)^4