What is the derivative of y=ln(-3x^6) ?

The derivative of y=ln(-3x^6) is 6/x

What is the first derivative of y=ln(-3x^6) ?

The first derivative of y=ln(-3x^6) is 6/x

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derivative of

y = ln (- 3 x^{6})

\frac{6}{x}

Solution steps

\frac{d}{d x} (ln (- 3 x^{6}))

Apply the chain rule:

\frac{1}{- 3 x ^{6}} \frac{d}{d x} (- 3 x^{6})

= \frac{1}{- 3 x ^{6}} \frac{d}{d x} (- 3 x^{6})

\frac{d}{d x} (- 3 x^{6}) = - 18 x^{5}

= \frac{1}{- 3 x ^{6}} (- 18 x^{5})

Simplify

\frac{1}{- 3 x ^{6}} (- 18 x^{5}) : \frac{6}{x}

= \frac{6}{x}

(1 + y^{2}) d x - (x^{2} + 1) d y = 0

\frac{\partial}{\partial x} (\frac{- y ^{4}}{4 x ^{4}})

\int (\frac{1}{1 - x}) d x

f (x) = 2 x^{2} + 2 x, (- 2, - 6)

\int_{0}^{2} ln (1 + x^{4}) d x

What is the derivative of y=ln(-3x^6) ?
The derivative of y=ln(-3x^6) is 6/x
What is the first derivative of y=ln(-3x^6) ?
The first derivative of y=ln(-3x^6) is 6/x