What is the limit as x approaches-1+of arccos(x) ?

The limit as x approaches-1+of arccos(x) is pi

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limit as x approaches-1+of arccos(x)

x \to - 1 + lim (arccos (x))

π

Decimal Notation

3.14159 \dots

Solution steps

x \to - 1 + lim (arccos (x))

Plug in the value

x = - 1

= arccos (- 1)

Use the following trivial identity:

arccos (- 1) = π

x - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 arccos (x) π \frac{5 π}{6} \frac{3 π}{4} \frac{2 π}{3} \frac{π}{2} \frac{π}{3} \frac{π}{4} \frac{π}{6} 0 arccos (x) 18 0^{\circ} 15 0^{\circ} 13 5^{\circ} 12 0^{\circ} 9 0^{\circ} 6 0^{\circ} 4 5^{\circ} 3 0^{\circ} 0^{\circ}

= π

2 y + (x + 1) \frac{d y}{d x} = 3 x + 3

\frac{480 t}{( t ^{2} + 5 ) ^{3}}

\int 5 e^{- 0.1 x} d x

x \to 1 lim (- 3 x + 5)

t \frac{d y}{d t} + (t + 1) y = 2 t e^{- t}

What is the limit as x approaches-1+of arccos(x) ?
The limit as x approaches-1+of arccos(x) is pi