What is the solution for t(dy)/(dt)+(t+1)y=2te^{-t} ?

The solution for t(dy)/(dt)+(t+1)y=2te^{-t} is y= t/(e^t)+(c_{1})/(e^tt)

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t(dy)/(dt)+(t+1)y=2te^{-t}

t \frac{d y}{d t} + (t + 1) y = 2 t e^{- t}

y = \frac{t}{e ^{t}} + \frac{c _{1}}{e ^{t} t}

Solution steps

t \frac{d y}{d t} + (t + 1) y = 2 t e^{- t}

Solve linear ODE:

y = \frac{t}{e ^{t}} + \frac{c _{1}}{e ^{t} t}

y = \frac{t}{e ^{t}} + \frac{c _{1}}{e ^{t} t}

3 x^{2} + 4 x - 2

y = \frac{3}{x}, at x = \frac{1}{16}

(x^{2} + 1) y^{^{'}} = x y

\frac{d}{d x} (ln (tan (x) + sec (x)))

\int cos^{2} (2 u) d u

What is the solution for t(dy)/(dt)+(t+1)y=2te^{-t} ?
The solution for t(dy)/(dt)+(t+1)y=2te^{-t} is y= t/(e^t)+(c_{1})/(e^tt)