What is the tangent of f(x)=6xcos(x),(pi,-6pi) ?

The tangent of f(x)=6xcos(x),(pi,-6pi) is y=-6x

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tangent of f(x)=6xcos(x),(pi,-6pi)

tangent of

f (x) = 6 x cos (x), (π, - 6 π)

y = - 6 x

Solution steps

Find the slope of

f (x) = 6 x cos (x) : \frac{df ( x )}{d x} = 6 (cos (x) - x sin (x))

Compute the slope of

f (x) = 6 x cos (x)

(π, - 6 π) : m = - 6

Find the line with slope m=

- 6

and passing through

(π, - 6 π) : y = - 6 x

y = - 6 x

\frac{d}{d x} (e^{2 x} - e^{- 2 x} - 4 x)

\frac{3}{x + 9}

y \cdot y^{^{'}} = \frac{5 x}{4 x ^{2} + 1}

\frac{x}{x ^{2} + 9}

What is the tangent of f(x)=6xcos(x),(pi,-6pi) ?
The tangent of f(x)=6xcos(x),(pi,-6pi) is y=-6x