What is the derivative of 2/(1+x^3) ?

The derivative of 2/(1+x^3) is -(6x^2)/((1+x^3)^2)

What is the first derivative of 2/(1+x^3) ?

The first derivative of 2/(1+x^3) is -(6x^2)/((1+x^3)^2)

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\frac{d}{d x} (\frac{2}{1 + x ^{3}})

- \frac{6 x ^{2}}{( 1 + x ^{3} ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{2}{1 + x ^{3}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (\frac{1}{1 + x ^{3}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 2 \frac{d}{d x} ((1 + x^{3})^{- 1})

Apply the chain rule:

- \frac{1}{( 1 + x ^{3} ) ^{2}} \frac{d}{d x} (1 + x^{3})

= - \frac{1}{( 1 + x ^{3} ) ^{2}} \frac{d}{d x} (1 + x^{3})

\frac{d}{d x} (1 + x^{3}) = 3 x^{2}

= 2 (- \frac{1}{( 1 + x ^{3} ) ^{2}} \cdot 3 x^{2})

Simplify

2 (- \frac{1}{( 1 + x ^{3} ) ^{2}} \cdot 3 x^{2}) : - \frac{6 x ^{2}}{( 1 + x ^{3} ) ^{2}}

= - \frac{6 x ^{2}}{( 1 + x ^{3} ) ^{2}}

\frac{s ^{2}}{( s - 3 ) ^{2}}

2 + 5 x^{2} - 2 x^{3}

f (x) = x^{2} - 7 x + 7, at x = 6

f (x) = (6 - 3 x) (6 + 3 x), at x = 3

\int_{- 0.5}^{0.5} 1.5 x^{2} d x

What is the derivative of 2/(1+x^3) ?
The derivative of 2/(1+x^3) is -(6x^2)/((1+x^3)^2)
What is the first derivative of 2/(1+x^3) ?
The first derivative of 2/(1+x^3) is -(6x^2)/((1+x^3)^2)