What is the integral of 1/(\sqrt[5]{x)} ?

The integral of 1/(\sqrt[5]{x)} is 5/4 x^{4/5}+C

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integral of 1/(\sqrt[5]{x)}

\frac{5}{4} x^{\frac{4}{5}} + C

Solution steps

Apply the Power Rule

: \frac{5}{4} x^{\frac{4}{5}}

= \frac{5}{4} x^{\frac{4}{5}}

Add a constant to the solution

= \frac{5}{4} x^{\frac{4}{5}} + C

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\frac{d}{d x} (x^{4} - 8 x^{2} + 16)

\frac{d}{d y} (\frac{1}{y ^{3}})

What is the integral of 1/(\sqrt[5]{x)} ?
The integral of 1/(\sqrt[5]{x)} is 5/4 x^{4/5}+C