What is the integral of (5x^3-3x^2+7) ?

The integral of (5x^3-3x^2+7) is (5x^4)/4-x^3+7x+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (5x^3-3x^2+7)

\int (5 x^{3} - 3 x^{2} + 7) d x

\frac{5 x ^{4}}{4} - x^{3} + 7 x + C

Solution steps

\int 5 x^{3} - 3 x^{2} + 7 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 5 x^{3} d x - \int 3 x^{2} d x + \int 7 d x

\int 5 x^{3} d x = \frac{5 x ^{4}}{4}

\int 3 x^{2} d x = x^{3}

\int 7 d x = 7 x

= \frac{5 x ^{4}}{4} - x^{3} + 7 x

Add a constant to the solution

= \frac{5 x ^{4}}{4} - x^{3} + 7 x + C

\frac{d}{d x} (x^{4} - 8 x^{2} + 16)

\frac{d}{d y} (\frac{1}{y ^{3}})

\frac{\partial}{\partial x} (2 x^{2} + 5 y^{2} - x y)

\int_{x}^{x^{2}} e^{t^{2}} d t

y = \frac{5 ( 1 - sin ( x ) )}{2 cos ( x )}

What is the integral of (5x^3-3x^2+7) ?
The integral of (5x^3-3x^2+7) is (5x^4)/4-x^3+7x+C