What is the derivative of y= 1/(2sqrt(x-2)) ?

The derivative of y= 1/(2sqrt(x-2)) is -1/(4(x-2)^{3/2)}

What is the first derivative of y= 1/(2sqrt(x-2)) ?

The first derivative of y= 1/(2sqrt(x-2)) is -1/(4(x-2)^{3/2)}

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derivative of

y = \frac{1}{2 x - 2}

- \frac{1}{4 ( x - 2 ) ^{\frac{3}{2}}}

Solution steps

\frac{d}{d x} (\frac{1}{2 x - 2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{2} \frac{d}{d x} (\frac{1}{x - 2})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{1}{2} \frac{d}{d x} ((x - 2)^{- \frac{1}{2}})

Apply the chain rule:

- \frac{1}{2 ( x - 2 ) ^{\frac{3}{2}}} \frac{d}{d x} (x - 2)

= - \frac{1}{2 ( x - 2 ) ^{\frac{3}{2}}} \frac{d}{d x} (x - 2)

\frac{d}{d x} (x - 2) = 1

= \frac{1}{2} (- \frac{1}{2 ( x - 2 ) ^{\frac{3}{2}}} \cdot 1)

Simplify

\frac{1}{2} (- \frac{1}{2 ( x - 2 ) ^{\frac{3}{2}}} \cdot 1) : - \frac{1}{4 ( x - 2 ) ^{\frac{3}{2}}}

= - \frac{1}{4 ( x - 2 ) ^{\frac{3}{2}}}

x \to 7 lim (\frac{2 x + 1}{x - 7})

\int 2 cos (5 x) d x

\frac{d y}{d x} = y (4 x^{2} + 1)

y = \frac{x}{3}

8 π^{7}

What is the derivative of y= 1/(2sqrt(x-2)) ?
The derivative of y= 1/(2sqrt(x-2)) is -1/(4(x-2)^{3/2)}
What is the first derivative of y= 1/(2sqrt(x-2)) ?
The first derivative of y= 1/(2sqrt(x-2)) is -1/(4(x-2)^{3/2)}