What is the solution for y^{''}+2y^'-15y=5e^{2t} ?

The solution for y^{''}+2y^'-15y=5e^{2t} is y=c_{1}e^{3t}+c_{2}e^{-5t}-5/7 e^{2t}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}+2y^'-15y=5e^{2t}

y^{^{''}} + 2 y^{^{'}} - 15 y = 5 e^{2 t}

y = c_{1} e^{3 t} + c_{2} e^{- 5 t} - \frac{5}{7} e^{2 t}

Solution steps

y^{''} (t) + 2 y^{'} (t) - 15 y = 5 e^{2 t}

Solve linear ODE:

y = c_{1} e^{3 t} + c_{2} e^{- 5 t} - \frac{5}{7} e^{2 t}

y = c_{1} e^{3 t} + c_{2} e^{- 5 t} - \frac{5}{7} e^{2 t}

\frac{\partial}{\partial x} (sin (x + y + z))

\int \frac{x + 16}{x ^{2} + 22 x + 125} d x

\int 9 cos^{2} (x t a) n^{3} x d x

\frac{\partial}{\partial x} (ln (x + 2 y + 3 z))

x \to + 0 + lim ((1 + x)^{\frac{2}{x}})

What is the solution for y^{''}+2y^'-15y=5e^{2t} ?
The solution for y^{''}+2y^'-15y=5e^{2t} is y=c_{1}e^{3t}+c_{2}e^{-5t}-5/7 e^{2t}