What is maclaurin 7/(1+x) ?

The answer to maclaurin 7/(1+x) is 7-7x+7x^2-7x^3+7x^4+\ldots

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maclaurin 7/(1+x)

maclaurin

\frac{7}{1 + x}

7 - 7 x + 7 x^{2} - 7 x^{3} + 7 x^{4} + \dots

Solution steps

Apply the Maclaurin Formula

= 7 + \frac{\frac{d}{d x} ( \frac{7}{1 + x} ) ( 0 )}{1 !} x + \frac{\frac{d ^{2}}{d x ^{2}} ( \frac{7}{1 + x} ) ( 0 )}{2 !} x^{2} + \frac{\frac{d ^{3}}{d x ^{3}} ( \frac{7}{1 + x} ) ( 0 )}{3 !} x^{3} + \dots

Evaluate Derivatives

= 7 + \frac{- 7}{1 !} x + \frac{14}{2 !} x^{2} + \frac{- 42}{3 !} x^{3} + \frac{168}{4 !} x^{4} + \dots

Refine

= 7 - 7 x + 7 x^{2} - 7 x^{3} + 7 x^{4} + \dots

\frac{\partial}{\partial x} (3 x^{2} y - 1)

\int \frac{6 x + 2}{x ^{2} + 9} d x

\frac{d}{d x} (\frac{x + 3}{x + 2})

\frac{d}{d x} (\frac{4}{4 - 10 x})

\frac{d}{d x} (\frac{x ^{2} - 2}{x})

What is maclaurin 7/(1+x) ?
The answer to maclaurin 7/(1+x) is 7-7x+7x^2-7x^3+7x^4+\ldots