What is area f(x)=x^2+4x-5,-3,3 ?

The answer to area f(x)=x^2+4x-5,-3,3 is 124/3

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area f(x)=x^2+4x-5,-3,3

area

f (x) = x^{2} + 4 x - 5, - 3, 3

\frac{124}{3}

Decimal Notation

41.33333 \dots

Solution steps

Apply the area formula:

\int_{- 3}^{3} x^{2} + 4 x - 5 d x

Solve

\int_{- 3}^{3} x^{2} + 4 x - 5 d x : \frac{124}{3}

The area is:

= \frac{124}{3}

x \to 3 lim (\frac{5 x}{x - 3})

\frac{d}{d x} (ln (\frac{3 x}{2 x + 1}))

\int \frac{1}{( x + 2 ) ( x + 7 ) ( 2 x - 5 ) ( x + 1 ) ^{2}} d x

y = x e^{- 0.4 x}, x = 5, y = 0

\frac{d}{d x} (2 + sin (x))

What is area f(x)=x^2+4x-5,-3,3 ?
The answer to area f(x)=x^2+4x-5,-3,3 is 124/3