What is the first derivative of bx ?

The first derivative of bx is b

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derivative of bx

\frac{d}{d x} (b x)

b

Solution steps

\frac{d}{d x} (b x)

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= b \frac{d x}{d x}

Apply the common derivative:

\frac{d x}{d x} = 1

= b \cdot 1

Simplify

= b

y^{^{'}} = t + 3

\frac{\partial}{\partial x} (\frac{( 3 x + 5 )}{6 y + 1})

\int_{0}^{2} π (4 x^{2} - x^{4}) d x

y = cos (x), at x = \frac{π}{4}

y^{^{''}} + y^{^{'}} - y = 0