What is the derivative of 2^n ?

The derivative of 2^n is 2^nln(2)

What is the first derivative of 2^n ?

The first derivative of 2^n is 2^nln(2)

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derivative of

2^{n}

2^{n} ln (2)

Solution steps

\frac{d}{d n} (2^{n})

Apply the derivative exponent rule:

\frac{d}{d x} (a^{x}) = a^{x} ln (a)

= 2^{n} ln (2)

\int \frac{cos ^{4} ( x )}{sin ( x )} d x

y^{^{'}} = x e^{x^{2} - 4}

y = ln (x^{3} + 4)

\frac{\partial}{\partial x} (6 x - 2 y)

y^{^{'}} = 4 x + y, y (0) = 7