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Popular >

y^'=4x+y,y(0)=7

Solution

y^{^{'}} = 4 x + y, y (0) = 7

Solution

y = - 4 (x + 1) + 11 e^{x}

Solution steps

y^{'} (x) = 4 x + y

Solve linear ODE:

y = - 4 (x + 1) + 11 e^{x}

y = - 4 (x + 1) + 11 e^{x}

Popular Examples

y^{''}-6y^'+9y=0,y(0)=2,y^'(0)=1

y^{^{''}} - 6 y^{^{'}} + 9 y = 0, y (0) = 2, y^{^{'}} (0) = 1

derivative of 2/(5x+3)derivative of

\frac{2}{5 x + 3}

integral of (csc^2(x))/(cot^3(x))

\int \frac{csc ^{2} ( x )}{cot ^{3} ( x )} d x

derivative of ln(4x^5+1)derivative of

ln (4 x^{5} + 1)

integral of cos^7(xta)n^3x

\int cos^{7} (x t a) n^{3} x d x

Frequently Asked Questions (FAQ)

What is the solution for y^'=4x+y,y(0)=7 ?
The solution for y^'=4x+y,y(0)=7 is y=-4(x+1)+11e^x