What is (\partial)/(\partial x)(ln(x+8y+9z)) ?

The answer to (\partial)/(\partial x)(ln(x+8y+9z)) is 1/(x+8y+9z)

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(\partial)/(\partial x)(ln(x+8y+9z))

\frac{\partial}{\partial x} (ln (x + 8 y + 9 z))

\frac{1}{x + 8 y + 9 z}

Solution steps

\frac{\partial}{\partial x} (ln (x + 8 y + 9 z))

Treat

y, z

as constants

Apply the chain rule:

\frac{1}{x + 8 y + 9 z} \frac{\partial}{\partial x} (x + 8 y + 9 z)

= \frac{1}{x + 8 y + 9 z} \frac{\partial}{\partial x} (x + 8 y + 9 z)

\frac{\partial}{\partial x} (x + 8 y + 9 z) = 1

= \frac{1}{x + 8 y + 9 z} \cdot 1

Simplify

= \frac{1}{x + 8 y + 9 z}

f (x) = \frac{( x ^{2} - 1 )}{( x ^{2} + x + 1 )}

x \to 1 - lim (\frac{x}{x + 1})

\frac{d}{d x} (\frac{2}{5 x ^{2} - 1})

y^{^{''}} + (\frac{2}{x}) y^{^{'}} = 0

\frac{\partial}{\partial x} (550 - 0.53 N^{2})

What is (\partial)/(\partial x)(ln(x+8y+9z)) ?
The answer to (\partial)/(\partial x)(ln(x+8y+9z)) is 1/(x+8y+9z)