What is the derivative of 2/(5x^2-1) ?

The derivative of 2/(5x^2-1) is -(20x)/((5x^2-1)^2)

What is the first derivative of 2/(5x^2-1) ?

The first derivative of 2/(5x^2-1) is -(20x)/((5x^2-1)^2)

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\frac{d}{d x} (\frac{2}{5 x ^{2} - 1})

- \frac{20 x}{( 5 x ^{2} - 1 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{2}{5 x ^{2} - 1})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (\frac{1}{5 x ^{2} - 1})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 2 \frac{d}{d x} ((5 x^{2} - 1)^{- 1})

Apply the chain rule:

- \frac{1}{( 5 x ^{2} - 1 ) ^{2}} \frac{d}{d x} (5 x^{2} - 1)

= - \frac{1}{( 5 x ^{2} - 1 ) ^{2}} \frac{d}{d x} (5 x^{2} - 1)

\frac{d}{d x} (5 x^{2} - 1) = 10 x

= 2 (- \frac{1}{( 5 x ^{2} - 1 ) ^{2}} \cdot 10 x)

Simplify

2 (- \frac{1}{( 5 x ^{2} - 1 ) ^{2}} \cdot 10 x) : - \frac{20 x}{( 5 x ^{2} - 1 ) ^{2}}

= - \frac{20 x}{( 5 x ^{2} - 1 ) ^{2}}

y^{^{''}} + (\frac{2}{x}) y^{^{'}} = 0

\frac{\partial}{\partial x} (550 - 0.53 N^{2})

2 + 9 sin (x^{2})

x^{^{''}} + 2 x^{^{'}} + x = 0

\int 3 - 2 x + x^{2} d x

What is the derivative of 2/(5x^2-1) ?
The derivative of 2/(5x^2-1) is -(20x)/((5x^2-1)^2)
What is the first derivative of 2/(5x^2-1) ?
The first derivative of 2/(5x^2-1) is -(20x)/((5x^2-1)^2)