What is area y=2x^3-13x,y=x^2+6 ?

The answer to area y=2x^3-13x,y=x^2+6 is 2459/48

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area y=2x^3-13x,y=x^2+6

area

y = 2 x^{3} - 13 x, y = x^{2} + 6

\frac{2459}{48}

Decimal Notation

51.22916 \dots

Solution steps

Apply the area formula:

\int_{- 2}^{3} 2 x^{3} - 13 x - (x^{2} + 6) d x

Solve

\int_{- 2}^{3} 2 x^{3} - 13 x - (x^{2} + 6) d x : \frac{2459}{48}

The area is:

= \frac{2459}{48}

x \to 1 - lim (x)

\frac{\partial}{\partial y} ((x + y) \cdot e^{x + 2 y})

\frac{2 x ^{2} - 3 x + 1}{x}

p

\frac{\partial}{\partial x} (2 x y + y^{2})

What is area y=2x^3-13x,y=x^2+6 ?
The answer to area y=2x^3-13x,y=x^2+6 is 2459/48