What is (\partial)/(\partial x)(4y^2-x^2) ?

The answer to (\partial)/(\partial x)(4y^2-x^2) is -2x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)(4y^2-x^2)

\frac{\partial}{\partial x} (4 y^{2} - x^{2})

- 2 x

Solution steps

\frac{\partial}{\partial x} (4 y^{2} - x^{2})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (4 y^{2}) - \frac{\partial}{\partial x} (x^{2})

\frac{\partial}{\partial x} (4 y^{2}) = 0

\frac{\partial}{\partial x} (x^{2}) = 2 x

= 0 - 2 x

Simplify

= - 2 x

\int_{- 1}^{5} x^{2} - 4 x - 5 d x

y^{^{'}} + 4 x y^{4} = 0

\frac{d}{d x} (\frac{x + 1 - 1}{x})

\frac{d}{d x} (x (24 - 2 x) (24 - 2 x))

x \to - 2 lim (\frac{5 x + 2}{x - 2})

What is (\partial)/(\partial x)(4y^2-x^2) ?
The answer to (\partial)/(\partial x)(4y^2-x^2) is -2x