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Popular >

y^'+4xy^4=0

Solution

y^{^{'}} + 4 x y^{4} = 0

Solution

Solution steps

y^{'} (x) + 4 x y^{4} = 0

Solve separable ODE:

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Frequently Asked Questions (FAQ)

What is the solution for y^'+4xy^4=0 ?
The solution for y^'+4xy^4=0 is y=-1/(\sqrt[3]{3(-2x^2+c_{1))}}