What is (\partial)/(\partial z)(z(1+e^{x+y})) ?

The answer to (\partial)/(\partial z)(z(1+e^{x+y})) is 1+e^{x+y}

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(\partial)/(\partial z)(z(1+e^{x+y}))

\frac{\partial}{\partial z} (z (1 + e^{x + y}))

1 + e^{x + y}

Solution steps

\frac{\partial}{\partial z} (z (1 + e^{x + y}))

Treat

x, y

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= (1 + e^{x + y}) \frac{\partial}{\partial z} (z)

Apply the common derivative:

\frac{\partial}{\partial z} (z) = 1

= (1 + e^{x + y}) \cdot 1

Simplify

= 1 + e^{x + y}

\frac{d}{d x} (3 x y^{2} + 2 y cos (x))

\int x^{2} (x^{3} - 1)^{4} d x

\frac{\partial}{\partial x} (\frac{x ^{2} y + 3 z y ^{3}}{x yz})

x y + y^{^{'}} = 80 x

\int_{3}^{4} (4 + \frac{24}{x ^{2}}) d x

What is (\partial)/(\partial z)(z(1+e^{x+y})) ?
The answer to (\partial)/(\partial z)(z(1+e^{x+y})) is 1+e^{x+y}