What is the derivative of ln(sqrt(2x-1)) ?

The derivative of ln(sqrt(2x-1)) is 1/(2x-1)

What is the first derivative of ln(sqrt(2x-1)) ?

The first derivative of ln(sqrt(2x-1)) is 1/(2x-1)

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derivative of

ln (2 x - 1)

\frac{1}{2 x - 1}

Solution steps

\frac{d}{d x} (ln (2 x - 1))

Apply the chain rule:

\frac{1}{2 x - 1} \frac{d}{d x} (2 x - 1)

= \frac{1}{2 x - 1} \frac{d}{d x} (2 x - 1)

\frac{d}{d x} (2 x - 1) = \frac{1}{2 x - 1}

= \frac{1}{2 x - 1} \cdot \frac{1}{2 x - 1}

Simplify

\frac{1}{2 x - 1} \cdot \frac{1}{2 x - 1} : \frac{1}{2 x - 1}

= \frac{1}{2 x - 1}

\frac{d y}{d x} + 4 y = e^{- x}

n = 1 \sum \infty \frac{n}{e ^{2 n}}

\int \frac{1}{x} d (x) d x

y^{^{'}} = \frac{( x + y + 1 )}{( - x + 2 y + 3 )}

\frac{\partial}{\partial y} (50 y + 3250 - 100 x)

What is the derivative of ln(sqrt(2x-1)) ?
The derivative of ln(sqrt(2x-1)) is 1/(2x-1)
What is the first derivative of ln(sqrt(2x-1)) ?
The first derivative of ln(sqrt(2x-1)) is 1/(2x-1)