What is the derivative of 3sin(x+1) ?

The derivative of 3sin(x+1) is 3cos(x)

What is the first derivative of 3sin(x+1) ?

The first derivative of 3sin(x+1) is 3cos(x)

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\frac{d}{d x} (3 sin (x) + 1)

3 cos (x)

Solution steps

\frac{d}{d x} (3 sin (x) + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 sin (x)) + \frac{d}{d x} (1)

\frac{d}{d x} (3 sin (x)) = 3 cos (x)

\frac{d}{d x} (1) = 0

= 3 cos (x) + 0

Simplify

= 3 cos (x)

\frac{d y}{d x} = e^{5 x + 4 y}

\int_{2}^{\infty} \frac{9}{2 x ^{2}} d x

\int 5 x cos (x) d x

\frac{( s + 2 )}{( s ^{2} + 3 s + 1 )}

\int \frac{5 x ^{3}}{( 5 - 3 x ^{4} ) ^{8}} d x

What is the derivative of 3sin(x+1) ?
The derivative of 3sin(x+1) is 3cos(x)
What is the first derivative of 3sin(x+1) ?
The first derivative of 3sin(x+1) is 3cos(x)