What is the derivative of f(x)=4x^2+2x-3 ?

The derivative of f(x)=4x^2+2x-3 is 8x+2

What is the first derivative of f(x)=4x^2+2x-3 ?

The first derivative of f(x)=4x^2+2x-3 is 8x+2

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derivative of

f (x) = 4 x^{2} + 2 x - 3

8 x + 2

Solution steps

\frac{d}{d x} (4 x^{2} + 2 x - 3)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4 x^{2}) + \frac{d}{d x} (2 x) - \frac{d}{d x} (3)

\frac{d}{d x} (4 x^{2}) = 8 x

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (3) = 0

= 8 x + 2 - 0

Simplify

= 8 x + 2

\int (cos (2 y) - 3 x^{2} y^{2}) d x

\frac{d}{d x} (\frac{1}{2 3 x - 1})

f (x) = 8 (x - \frac{1}{x})^{4}, at x = 2

(sin (x^{'}))^{^{'}}

x - 2 + \frac{( x + 1 ) ^{2}}{2}

What is the derivative of f(x)=4x^2+2x-3 ?
The derivative of f(x)=4x^2+2x-3 is 8x+2
What is the first derivative of f(x)=4x^2+2x-3 ?
The first derivative of f(x)=4x^2+2x-3 is 8x+2