What is the tangent of f(x)=8(x-1/x)^4,\at x=2 ?

The tangent of f(x)=8(x-1/x)^4,\at x=2 is y=135x-459/2

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tangent of f(x)=8(x-1/x)^4,\at x=2

tangent of

f (x) = 8 (x - \frac{1}{x})^{4}, at x = 2

y = 135 x - \frac{459}{2}

Solution steps

Find the tangent point:

(2, \frac{81}{2})

Find the slope of

f (x) = 8 (x - \frac{1}{x})^{4} : \frac{df ( x )}{d x} = 32 (x - \frac{1}{x})^{3} (1 + \frac{1}{x ^{2}})

Compute the slope of

f (x) = 8 (x - \frac{1}{x})^{4}

x = 2 : m = 135

Find the line with slope m=

135

and passing through

(2, \frac{81}{2}) : y = 135 x - \frac{459}{2}

y = 135 x - \frac{459}{2}

(sin (x^{'}))^{^{'}}

x - 2 + \frac{( x + 1 ) ^{2}}{2}

\int_{0}^{1} π (y - y^{2}) d y

\frac{\partial}{\partial x} (x e^{z})

What is the tangent of f(x)=8(x-1/x)^4,\at x=2 ?
The tangent of f(x)=8(x-1/x)^4,\at x=2 is y=135x-459/2