What is the derivative of \sqrt[3]{t^2}+4sqrt(t^5) ?

The derivative of \sqrt[3]{t^2}+4sqrt(t^5) is (2t)/(3(t^2)^{2/3)}+10t^{3/2}

What is the first derivative of \sqrt[3]{t^2}+4sqrt(t^5) ?

The first derivative of \sqrt[3]{t^2}+4sqrt(t^5) is (2t)/(3(t^2)^{2/3)}+10t^{3/2}

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derivative of

\frac{2 t}{3 ( t ^{2} ) ^{\frac{2}{3}}} + 10 t^{\frac{3}{2}}

Solution steps

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

\frac{d}{d t} (4 t^{5}) = 10 t^{\frac{3}{2}}

= \frac{2 t}{3 ( t ^{2} ) ^{\frac{2}{3}}} + 10 t^{\frac{3}{2}}

\frac{\partial}{\partial x} (x e^{z})

\int e^{i t} d t

x \to \infty lim (\frac{7}{x} - 1)

y^{^{''}} + 5 y^{^{'}} + 4 y = sin (t)

\frac{d}{d x} ((\frac{x}{1 + x})^{5})

What is the derivative of \sqrt[3]{t^2}+4sqrt(t^5) ?
The derivative of \sqrt[3]{t^2}+4sqrt(t^5) is (2t)/(3(t^2)^{2/3)}+10t^{3/2}
What is the first derivative of \sqrt[3]{t^2}+4sqrt(t^5) ?
The first derivative of \sqrt[3]{t^2}+4sqrt(t^5) is (2t)/(3(t^2)^{2/3)}+10t^{3/2}