What is the limit as x approaches infinity of 7/x-1 ?

The limit as x approaches infinity of 7/x-1 is -1

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limit as x approaches infinity of 7/x-1

x \to \infty lim (\frac{7}{x} - 1)

- 1

Solution steps

x \to \infty lim (\frac{7}{x} - 1)

x \to a lim [f (x) \pm g (x)] = x \to a lim f (x) \pm x \to a lim g (x)

With the exception of indeterminate form

= x \to \infty lim (\frac{7}{x}) - x \to \infty lim (1)

x \to \infty lim (\frac{7}{x}) = 0

x \to \infty lim (1) = 1

= 0 - 1

Simplify

= - 1

y^{^{''}} + 5 y^{^{'}} + 4 y = sin (t)

\frac{d}{d x} ((\frac{x}{1 + x})^{5})

- 3 t (2 t^{4} - 1)^{7}

f (x) = ln (8 - 9 x)

7 x^{2}, \frac{1}{7} x

What is the limit as x approaches infinity of 7/x-1 ?
The limit as x approaches infinity of 7/x-1 is -1