What is the derivative of-3t(2t^4-1)^7 ?

The derivative of-3t(2t^4-1)^7 is -3((2t^4-1)^7+56t^4(2t^4-1)^6)

What is the first derivative of-3t(2t^4-1)^7 ?

The first derivative of-3t(2t^4-1)^7 is -3((2t^4-1)^7+56t^4(2t^4-1)^6)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

- 3 t (2 t^{4} - 1)^{7}

- 3 ((2 t^{4} - 1)^{7} + 56 t^{4} (2 t^{4} - 1)^{6})

Solution steps

\frac{d}{d t} (- 3 t (2 t^{4} - 1)^{7})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 3 \frac{d}{d t} (t (2 t^{4} - 1)^{7})

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = t, g = (2 t^{4} - 1)^{7}

= - 3 (\frac{d t}{d t} (2 t^{4} - 1)^{7} + \frac{d}{d t} ((2 t^{4} - 1)^{7}) t)

\frac{d t}{d t} = 1

\frac{d}{d t} ((2 t^{4} - 1)^{7}) = 56 t^{3} (2 t^{4} - 1)^{6}

= - 3 (1 \cdot (2 t^{4} - 1)^{7} + 56 t^{3} (2 t^{4} - 1)^{6} t)

Simplify

- 3 (1 \cdot (2 t^{4} - 1)^{7} + 56 t^{3} (2 t^{4} - 1)^{6} t) : - 3 ((2 t^{4} - 1)^{7} + 56 t^{4} (2 t^{4} - 1)^{6})

= - 3 ((2 t^{4} - 1)^{7} + 56 t^{4} (2 t^{4} - 1)^{6})

f (x) = ln (8 - 9 x)

7 x^{2}, \frac{1}{7} x

\int \frac{3 x}{x ^{2} + 4} d x

\frac{\partial}{\partial x} (4 x y + x^{4} + y^{4})

\frac{d}{d x} (y - x)

What is the derivative of-3t(2t^4-1)^7 ?
The derivative of-3t(2t^4-1)^7 is -3((2t^4-1)^7+56t^4(2t^4-1)^6)
What is the first derivative of-3t(2t^4-1)^7 ?
The first derivative of-3t(2t^4-1)^7 is -3((2t^4-1)^7+56t^4(2t^4-1)^6)