What is the integral of 3sin(x)-2cos(x) ?

The integral of 3sin(x)-2cos(x) is -3cos(x)-2sin(x)+C

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integral of 3sin(x)-2cos(x)

\int 3 sin (x) - 2 cos (x) d x

- 3 cos (x) - 2 sin (x) + C

Solution steps

\int 3 sin (x) - 2 cos (x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 3 sin (x) d x - \int 2 cos (x) d x

\int 3 sin (x) d x = - 3 cos (x)

\int 2 cos (x) d x = 2 sin (x)

= - 3 cos (x) - 2 sin (x)

Add a constant to the solution

= - 3 cos (x) - 2 sin (x) + C

y = 70 x^{- 4}

\int_{0}^{1} sin^{2} (x) d x

\frac{d}{d x} (x + h)

y = \frac{x}{x + 1}

x \to 0 lim (\frac{x ^{2}}{x - 2})

What is the integral of 3sin(x)-2cos(x) ?
The integral of 3sin(x)-2cos(x) is -3cos(x)-2sin(x)+C