What is (\partial)/(\partial z)(ycos(z)) ?

The answer to (\partial)/(\partial z)(ycos(z)) is -ysin(z)

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(\partial)/(\partial z)(ycos(z))

\frac{\partial}{\partial z} (y cos (z))

- y sin (z)

Solution steps

\frac{\partial}{\partial z} (y cos (z))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= y \frac{\partial}{\partial z} (cos (z))

Apply the common derivative:

\frac{\partial}{\partial z} (cos (z)) = - sin (z)

= y (- sin (z))

Simplify

= - y sin (z)

3 x + 3 x

\frac{y ^{2}}{2} = x, x = 2 y

\int 5 (9 x - 4)^{4} d x

\int (1 0^{x} - \frac{1}{x}) d x

\frac{d}{d x} (x^{2} + 6 x + 10)

What is (\partial)/(\partial z)(ycos(z)) ?
The answer to (\partial)/(\partial z)(ycos(z)) is -ysin(z)