What is the integral from 0 to pi of 2cos^2(pi/2) ?

The integral from 0 to pi of 2cos^2(pi/2) is 0

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integral from 0 to pi of 2cos^2(pi/2)

\int_{0}^{π} 2 cos^{2} (\frac{π}{2}) d x

0

Solution steps

\int_{0}^{π} 2 cos^{2} (\frac{π}{2}) d x

Integral of a constant:

\int a d x = a x

= [2 cos^{2} (\frac{π}{2}) x]_{0}^{π}

Simplify

[2 cos^{2} (\frac{π}{2}) x]_{0}^{π} : [0]_{0}^{π}

= [0]_{0}^{π}

Compute the boundaries:

0

= 0

\int \frac{2}{7} x^{2} + 1 d x

f (x) = 3 x^{2}, (- 1, 3)

g (t) = t

\frac{d}{d x} ((x^{2} + 2 x + 2)^{s i n (x)})

y^{^{'}} + y = x y^{4}

What is the integral from 0 to pi of 2cos^2(pi/2) ?
The integral from 0 to pi of 2cos^2(pi/2) is 0