What is the tangent of f(x)=x^2-49x-456,\at x=2 ?

The tangent of f(x)=x^2-49x-456,\at x=2 is y=-45x-460

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tangent of f(x)=x^2-49x-456,\at x=2

tangent of

f (x) = x^{2} - 49 x - 456, at x = 2

y = - 45 x - 460

Solution steps

Find the tangent point:

(2, - 550)

Find the slope of

f (x) = x^{2} - 49 x - 456 : \frac{df ( x )}{d x} = 2 x - 49

Compute the slope of

f (x) = x^{2} - 49 x - 456

x = 2 : m = - 45

Find the line with slope m=

- 45

and passing through

(2, - 550) : y = - 45 x - 460

y = - 45 x - 460

\frac{d}{d x} (1 + cot^{2} (x))

\int (x^{2} + 8) e^{- x} d x

x \to \infty lim (\frac{6}{x})

y = 3 x + 1, (5, 16)

\frac{c ^{2} - x ^{2}}{c ^{2} + x ^{2}}

What is the tangent of f(x)=x^2-49x-456,\at x=2 ?
The tangent of f(x)=x^2-49x-456,\at x=2 is y=-45x-460