What is the integral of 4x^{-1} ?

The integral of 4x^{-1} is 4ln|x|+C

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integral of 4x^{-1}

\int 4 x^{- 1} d x

4 ln ∣ x ∣ + C

Solution steps

\int 4 x^{- 1} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 \cdot \int x^{- 1} d x

Use the common integral:

\int x^{- 1} d x = ln (∣ x ∣)

= 4 ln ∣ x ∣

Add a constant to the solution

= 4 ln ∣ x ∣ + C

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