What is the integral from 0 to t of cos(x^2) ?

The integral from 0 to t of cos(x^2) is sqrt(pi/2)\C(sqrt(2/pi)t)-sqrt(pi/2)\C(sqrt(2/pi)*0)

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integral from 0 to t of cos(x^2)

\int_{0}^{t} cos (x^{2}) d x

\frac{π}{2} C (\frac{2}{π} t) - \frac{π}{2} C (\frac{2}{π} \cdot 0)

Solution steps

\int_{0}^{t} cos (x^{2}) d x

Use the nonelementary integral:

\int cos (x^{2}) d x = \frac{π}{2} C (\frac{2}{π} x)

= [\frac{π}{2} C (\frac{2}{π} x)]_{0}^{t}

Compute the boundaries:

\frac{π}{2} C (\frac{2}{π} t) - \frac{π}{2} C (\frac{2}{π} \cdot 0)

= \frac{π}{2} C (\frac{2}{π} t) - \frac{π}{2} C (\frac{2}{π} \cdot 0)

\frac{\partial}{\partial x} (cos (4 θ))

\int \frac{sin ^{2} ( x )}{1 + cos ( x )} d x

y = x + cos (x)

\frac{d}{d x} (\frac{x}{1})

f (x) = \frac{12 x}{1 - x}

What is the integral from 0 to t of cos(x^2) ?
The integral from 0 to t of cos(x^2) is sqrt(pi/2)\C(sqrt(2/pi)t)-sqrt(pi/2)\C(sqrt(2/pi)*0)