What is the derivative of (e^x/y) ?

The derivative of (e^x/y) is (e^xy-\frac{dy)/(dx)e^x}{y^2}

What is the first derivative of (e^x/y) ?

The first derivative of (e^x/y) is (e^xy-\frac{dy)/(dx)e^x}{y^2}

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\frac{d}{d x} (\frac{e ^{x}}{y})

\frac{e ^{x} y - \frac{d y}{d x} e ^{x}}{y ^{2}}

Solution steps

\frac{d}{d x} (\frac{e ^{x}}{y})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( e ^{x} ) y - \frac{d y}{d x} e ^{x}}{y ^{2}}

\frac{d}{d x} (e^{x}) = e^{x}

= \frac{e ^{x} y - \frac{d y}{d x} e ^{x}}{y ^{2}}

f (x) = 3 x^{2} - ln (x)

\frac{2}{x}, 3

x^{2} y^{^{''}} + x y^{^{'}} - y = \frac{1}{x}

\frac{d y}{d x} = (\frac{4 y + 3}{8 x + 5})^{2}

\int cos (x^{2}) x d x

What is the derivative of (e^x/y) ?
The derivative of (e^x/y) is (e^xy-\frac{dy)/(dx)e^x}{y^2}
What is the first derivative of (e^x/y) ?
The first derivative of (e^x/y) is (e^xy-\frac{dy)/(dx)e^x}{y^2}