What is the integral from-1 to 1 of (x^2-2x+3) ?

The integral from-1 to 1 of (x^2-2x+3) is 20/3

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integral from-1 to 1 of (x^2-2x+3)

\int_{- 1}^{1} (x^{2} - 2 x + 3) d x

\frac{20}{3}

Decimal Notation

6.66666 \dots

Solution steps

\int_{- 1}^{1} x^{2} - 2 x + 3 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{1} x^{2} d x - \int_{- 1}^{1} 2 x d x + \int_{- 1}^{1} 3 d x

\int_{- 1}^{1} x^{2} d x = \frac{2}{3}

\int_{- 1}^{1} 2 x d x = 0

\int_{- 1}^{1} 3 d x = 6

= \frac{2}{3} - 0 + 6

Simplify

\frac{2}{3} - 0 + 6 : \frac{20}{3}

= \frac{20}{3}

\frac{\partial}{\partial x} (y^{4} - 6 x y)

y^{^{'}} + 4 y = e^{3 x}

x \to 0 lim (\frac{1}{1})

\int (x^{2} + 6) sin (2 x) d x

ln (e + x)

What is the integral from-1 to 1 of (x^2-2x+3) ?
The integral from-1 to 1 of (x^2-2x+3) is 20/3