What is the derivative of 2x^2+5x ?

The derivative of 2x^2+5x is 4x+5

What is the first derivative of 2x^2+5x ?

The first derivative of 2x^2+5x is 4x+5

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derivative of

2 x^{2} + 5 x

4 x + 5

Solution steps

\frac{d}{d x} (2 x^{2} + 5 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{2}) + \frac{d}{d x} (5 x)

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (5 x) = 5

= 4 x + 5

x \to 0 lim (x^{3} sin (\frac{1}{x}))

f (x) = 2 sec (x)

f (x) = π^{9}

\frac{18}{( x - 6 ) ^{2}}

y^{^{''}} + 6 y^{^{'}} + 9 y = t + e^{3 t}

What is the derivative of 2x^2+5x ?
The derivative of 2x^2+5x is 4x+5
What is the first derivative of 2x^2+5x ?
The first derivative of 2x^2+5x is 4x+5