What is inverse oflaplace 1/((s-1)) ?

The answer to inverse oflaplace 1/((s-1)) is e^t

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inverse oflaplace 1/((s-1))

inverse laplace

\frac{1}{( s - 1 )}

e^{t}

Solution steps

L^{- 1} {\frac{1}{( s - 1 )}}

Use Inverse Laplace Transform table:

L^{- 1} {\frac{1}{s - a}} = e^{a t}

L^{- 1} {\frac{1}{s - 1}} = e^{t}

= e^{t}

f (x) = x^{2} - 7, (2, - 3)

\frac{d}{d x} ((ln (x + 1))^{2})

y = 9 x, y = x^{2} - 10, y = 0

y^{^{'}} + 3 x^{2} y = 0

What is inverse oflaplace 1/((s-1)) ?
The answer to inverse oflaplace 1/((s-1)) is e^t