What is the derivative of f(x)=x^4+3x ?

The derivative of f(x)=x^4+3x is 4x^3+3

What is the first derivative of f(x)=x^4+3x ?

The first derivative of f(x)=x^4+3x is 4x^3+3

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derivative of

f (x) = x^{4} + 3 x

4 x^{3} + 3

Solution steps

\frac{d}{d x} (x^{4} + 3 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{4}) + \frac{d}{d x} (3 x)

\frac{d}{d x} (x^{4}) = 4 x^{3}

\frac{d}{d x} (3 x) = 3

= 4 x^{3} + 3

\frac{1}{1 - 2 x}

(sin (x) + x cos (x))^{^{'}}

\int \frac{2 e ^{2 x}}{e ^{10} - 1} d x

\int \frac{1}{( 121 + x ^{2} ) ^{2}} d x

\int \frac{( x ^{2} + 2 x - 2 )}{x ^{3} - 4 x} d x

What is the derivative of f(x)=x^4+3x ?
The derivative of f(x)=x^4+3x is 4x^3+3
What is the first derivative of f(x)=x^4+3x ?
The first derivative of f(x)=x^4+3x is 4x^3+3