What is the solution for (y^2sin(x))dx+(1/x-y/x)dy=0 ?

The solution for (y^2sin(x))dx+(1/x-y/x)dy=0 is y= 1/(-xcos(x)+sin(x)+c_{1)}

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(y^2sin(x))dx+(1/x-y/x)dy=0

(y^{2} sin (x)) d x + (\frac{1}{x} - \frac{y}{x}) d y = 0

y = \frac{1}{- x cos ( x ) + sin ( x ) + c _{1}}

Solution steps

(y^{2} sin (x)) d x + (\frac{1}{x} - \frac{y}{x}) d y = 0

Solve Bernoulli ODE:

y = \frac{1}{- x cos ( x ) + sin ( x ) + c _{1}}

y = \frac{1}{- x cos ( x ) + sin ( x ) + c _{1}}

x \to 4 lim (\frac{8 - 2 x}{x - 4})

\frac{d}{d x} (\frac{1}{( x - 4 ) ^{2}})

y = \frac{d y}{d x}

\int \frac{1}{x ^{2} ( x - 1 )} d x

\frac{\partial}{\partial x} ((x y + x + y) e^{x})

What is the solution for (y^2sin(x))dx+(1/x-y/x)dy=0 ?
The solution for (y^2sin(x))dx+(1/x-y/x)dy=0 is y= 1/(-xcos(x)+sin(x)+c_{1)}