What is the derivative of (3x-1^4) ?

The derivative of (3x-1^4) is 12(3x-1)^3

What is the first derivative of (3x-1^4) ?

The first derivative of (3x-1^4) is 12(3x-1)^3

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\frac{d}{d x} ((3 x - 1)^{4})

12 (3 x - 1)^{3}

Solution steps

\frac{d}{d x} ((3 x - 1)^{4})

Apply the chain rule:

4 (3 x - 1)^{3} \frac{d}{d x} (3 x - 1)

= 4 (3 x - 1)^{3} \frac{d}{d x} (3 x - 1)

\frac{d}{d x} (3 x - 1) = 3

= 4 (3 x - 1)^{3} \cdot 3

Simplify

= 12 (3 x - 1)^{3}

\frac{d}{d x} (- cos (2 x) - sin (2 x) - \frac{1}{5} e^{x})

2 \frac{d y}{d x} + 6 y = 3

\frac{d}{d x} ((2 x^{3} - 3 x + 2)^{4})

x \to 2 - lim (\frac{x + 2}{x - 3})

\int \frac{x ^{2}}{x ^{3} + 2} d x

What is the derivative of (3x-1^4) ?
The derivative of (3x-1^4) is 12(3x-1)^3
What is the first derivative of (3x-1^4) ?
The first derivative of (3x-1^4) is 12(3x-1)^3